Exam Cheat Sheet · Quick Reference
ICC F32 Residential Mechanical (Class C) Exam (2015 IRC)
National · Pearson Vue
National State Portion 70 questions
Key Distinctions
Horizontal ducts require each opening to have not less than 1 square inch of free area per 2,000 Btu/h of total input, while direct openings or vertical ducts require only 1 square inch per 4,000 Btu/h per opening (2015 IRC G2407.6.1).
IRC 2015 Section G2407.6.1 (304.6.1)The one-opening method requires 1 square inch per 3,000 Btu/h of total input and not less than the sum of the areas of all vent connectors in the enclosure, versus the two-opening rates of 1 per 2,000 (horizontal duct) or 1 per 4,000 Btu/h (direct/vertical) each.
IRC 2015 Section G2407.6.2 (304.6.2)Where the design and free area are not known, wood louvers are assumed to have 25-percent free area and metal louvers and grilles are assumed to have 75-percent free area (G2407.10 / M1307.4.1.2).
IRC 2015 Section G2407.10 (304.10)Where the free area through a louver, grille or screen design is known, that known free area is used to size the opening; only where it is unknown are the 25-percent (wood) and 75-percent (metal) assumptions applied.
IRC 2015 Section G2407.10 (304.10)The standard method requires 50 cubic feet per 1,000 Btu/h of total input, while the known-air-infiltration-rate method uses Equation 24-1 or 24-2 and must be used where the known infiltration rate is less than 0.40 ACH.
IRC 2015 Section G2407.5.1 (304.5.1)Equation 24-1 uses the 21/ACH factor for other-than-fan-assisted appliances and Equation 24-2 uses the 15/ACH factor for fan-assisted appliances (G2407.5.2).
IRC 2015 Section G2407.5.2 (304.5.2)Same-story openings require each opening to have 1 square inch per 1,000 Btu/h of total input but not less than 100 square inches, while spaces in different stories are considered communicating where openings in doors or floors provide a total minimum free area of 2 square inches per 1,000 Btu/h.
IRC 2015 Section G2407.5.3.1 (304.5.3.1)Category I natural-draft and draft-hood-equipped gas appliances use the prescriptive methods of G2407.5 through G2407.9, while direct-vent appliances, gas appliances of other than natural draft design, vented gas appliances not designated as Category I, appliances with power burners, and solid fuel-burning appliances (M1701.1) follow the manufacturer's instructions.
IRC 2015 Section G2407.1 (304.1)Slab-on-grade requires insulating material with a minimum R-value of 5 beneath the piping (M2103.2.1), while suspended floor applications require minimum R-11 insulation in the joist bay cavity serving the heated space above (M2103.2.2).
IRC 2015 Section M2103.2.1The exhaust duct maximum length is 35 feet from the connection to the transition duct to the outlet terminal (reduced for fittings per Table M1502.4.5.1), while the transition duct is a single listed length not greater than 8 feet, not concealed in construction, and not counted in the 35 feet.
IRC 2015 Section M1502.4.5.1The passageway from the attic opening to the appliance is limited to not more than 20 feet measured along the centerline; 50 feet is permitted only where the passageway is unobstructed and not less than 6 feet high and 22 inches wide for its entire length (M1305.1.3).
IRC 2015 Section M1305.1.3A draft hood is a nonadjustable device built into an appliance or vent connector that permits escape of flue gases with no draft, prevents backdraft entry and neutralizes stack action, while a barometric draft regulator is a balanced damper device attached to a chimney, vent connector, breeching or flue gas manifold that controls chimney draft (double-acting types move either way to protect against excessive draft and backdraft).
IRC 2015 Section G2403 (202) — definition of DRAFT HOODConcealed mechanical piping shield plates must be steel not less than 0.0575 inch (No. 16 gage) per M1308.2.3, whereas 0.062 inch applies to dryer exhaust duct shield plates (M1502.5) and 0.0157 inch (No. 28 gage) is the minimum dryer duct metal thickness.
IRC 2015 Section M1308.2.3Key Terms
Formulas to Know
Required volume = 50 cubic feet per 1,000 Btu/h of total appliance input (example: 150,000 Btu/h ÷ 1,000 = 150; 150 × 50 = 7,500 cu ft) — G2407.5.1Other than fan-assisted (Eq. 24-1): Required Volume ≥ (21/ACH) × (I ÷ 1,000 Btu/h); fan-assisted (Eq. 24-2): Required Volume ≥ (15/ACH) × (I_fan ÷ 1,000 Btu/h); total for the space is the sum of the volumes for all appliances; this method must be used where the known infiltration rate is less than 0.40 ACH (example: 0.30 ACH with a 60,000 Btu/h fan-assisted + 30,000 Btu/h natural-draft = 3,000 + 2,100 = 5,100 cu ft)Each opening: 1 sq in free area per 2,000 Btu/h of total input where communicating through horizontal ducts; 1 sq in per 4,000 Btu/h where communicating directly with the outdoors or through vertical ducts (examples: 120,000 ÷ 2,000 = 60 sq in each; 100,000 ÷ 4,000 = 25 sq in each) — G2407.6.1Opening free area = 1 sq in per 3,000 Btu/h of total input of all appliances in the enclosure, and not less than the sum of the areas of all vent connectors (example: 120,000 ÷ 3,000 = 40 sq in, which exceeds 28 sq in of vent connector area) — G2407.6.2Same story: each opening = 1 sq in per 1,000 Btu/h of total input, not less than 100 sq in (example: 150,000 ÷ 1,000 = 150 sq in each). Different stories: openings in doors or floors with total minimum free area of 2 sq in per 1,000 Btu/h (example: 2 × 75 = 150 sq in) — G2407.5.3.1 / G2407.5.3.2Ratio of interior spaces = available volume ÷ required volume; reduction factor = 1 − ratio; required outdoor opening = full opening size from G2407.6 × reduction factor (example: 2,400 ÷ 6,000 = 0.4; 1 − 0.4 = 0.6; horizontal-duct opening 120,000 ÷ 2,000 = 60 sq in; 60 × 0.6 = 36 sq in each); minimum opening dimension still not less than 3 inches — G2407.7.3Outdoor air not less than 0.35 cfm per 1,000 Btu/h of the TOTAL input rating of all appliances in the space (example: 150,000 Btu/h → 150 × 0.35 = 52.5 cfm; 35 cfm ÷ 0.35 = 100,000 Btu/h maximum input); each appliance must be interlocked with the air supply system (G2407.9.2) — G2407.9Total outdoor airflow = required ventilation air + combustion air at 0.35 cfm per 1,000 Btu/h (example: 60 cfm ventilation + (100 × 0.35 = 35 cfm) = 95 cfm) — G2407.9.3Gross opening = required net free area ÷ louver free-area percentage; use the known free area where known (44 ÷ 0.55 = 80 sq in); where design and free area are unknown use 25% for wood (60 ÷ 0.25 = 240 sq in) and 75% for metal (90 ÷ 0.75 = 120 sq in) — G2407.10Test at 1.5 × maximum system design pressure, but not less than 100 psi (example: 1.5 × 50 psi = 75 psi, so the 100 psi minimum governs); hold not less than 15 and not more than 20 minutes — M2101.10Installed thickness = (actual outside diameter − nominal inside diameter) ÷ 2; nominal thickness is used for duct board and rigid ducts, and 75 percent of nominal (25-percent compression) for ductwrap — M1601.3, item 4