Exam Cheat Sheet · Quick Reference
Oklahoma HVACR Journeyman Limited
Oklahoma · PSI Services Contractor
Oklahoma State Portion 60 questions
Key Distinctions
A pictorial diagram shows all connections plus the approximate physical location of devices in the unit (and often wire colors), while a ladder diagram shows the order of component operation as horizontal rungs between two vertical power lines, with devices near the top energized first.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 18 - Electrical Troubleshooting Fundamentals, Page 369 (Section 18.2.2) (20th ed.: Chapter 16, Section 16.1.1)A current relay switches on run-winding current magnitude (terminals L = line, M = main/run winding, S = start winding; its contacts open as the motor accelerates and run-winding current drops), while a potential relay actuates on the counter electromotive force (cemf) built up in the start winding at about three-fourths of rated speed.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 339 (Section 17.4.5) (20th ed.: Chapter 16, Section 16.3.5 — Current Relays)An SSR switches circuits electronically with transistors, SCRs, or triacs with no physical movement of mechanical parts, whereas an electromagnetic relay uses mechanical contacts.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 345 ("Solid-State Relays") (20th ed.: Chapter 16, Section 16.3.5 — Solid-State Relays)Turning the range screw clockwise raises both cut-in and cut-out an equal amount (differential unchanged), while the differential screw turned clockwise raises only the cut-out pressure and leaves cut-in unaffected.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 333 (Section 17.4.4) (20th ed.: Chapter 16, Section 16.3.4 — Low-Pressure Motor Controls)Subcooling is generally used to check charge on systems with thermostatic expansion valves (low subcooling = possible undercharge, high = possible overcharge), while superheat is used on fixed-orifice systems such as capillary tubes.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 12 - Working with Refrigerants, Page 221 (20th ed.: Page 236)BRI is a specifically diagnosable illness caused by exposure to airborne agents whose symptoms do not disappear when the occupant leaves, while SBS has no specific cause or identifiable illness and its symptoms disappear when occupants leave the building.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 29 - Air Quality, Page 647 (20th ed.: Page 730)K-value is heat passing through one square foot of material one inch thick in one hour per 1°F difference (Btu·in/hr·ft²·°F), while C-value is based on the material's actual measured thickness rather than a standardized 1-inch thickness.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 32 - Heating and Cooling Loads, Page 717 (20th ed.: Page 986)An in-line ammeter must be wired in series with the load (on dc, black lead to negative and red to positive), while a clamp-on ammeter encircles a single conductor — clamping both hot and neutral makes the opposing magnetic fields cancel and the meter reads zero.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 18 - Electrical Troubleshooting Fundamentals, Page 362 ("In-Line Ammeters") (20th ed.: Chapter 17, Section 17.1.3 — In-Line Ammeters)Per the IECC, maximum leakage is 3 cfm per 100 ft² of conditioned space when tested before the air handler is installed, versus 4 cfm per 100 ft² when tested with the air handler installed.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 31 - Ventilation System Service, Page 703 (Section 31.1.5) (20th ed.: Page 793)A radial system runs individual branch ducts directly from a central plenum to each outlet with no trunk line, while a perimeter loop system is used with downflow furnaces in slab homes without basements, with branches feeding a perimeter duct embedded in the slab.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 30 - Air Distribution, Page 672 (20th ed.: Page 755)In an HSI system the glow coil is used only for ignition and cannot sense flame; a separate flame rod proves the flame by rectification, so a dirty or oxidized rod lets the burner light and then shuts off seconds later (HSI systems do not use thermocouples).
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 33 - Gas-Fired Heating Systems, Page 765 (20th ed.: Pages 1126-1128 (Sections 41.5.4 and 41.6.1))A current-limiting fuse uses temperature-sensitive resistors that open when current exceeds the limit and reclose when cooled (keeping motor current below rated locked rotor amperage), while a multipurpose fuse combines fast-acting and time-delay traits — it rides through small short-duration overloads such as motor starting but blows immediately above 500% of maximum rating.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 347 (Section 17.5.1) (20th ed.: Chapter 16, Section 16.4.1)A three-phase supply is already phase-split (the three currents peak at different times), so no start windings or capacitors are needed, and power is constant because voltages are never all zero at once; single-phase motors must create phase splitting.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 16 - Electric Motors, Page 308 (Section 16.2.2) (20th ed.: Chapter 15, Section 15.2.2)Key Terms
Formulas to Know
R = E ÷ I and I = E ÷ R; e.g., 240 V ÷ 10 A = 24 Ω, and in a series circuit 24 V ÷ 8 Ω = 3 A flowing equally through every load.P = I × E; e.g., 20 A × 120 V = 2400 W, 15 A × 240 V = 3600 W, 8 A × 240 V = 1920 W.Differential = higher value − lower value: for a heating system cut-out − cut-in (74°F − 68°F = 6°F), for a cooling system cut-in − cut-out; in a series circuit the sum of all individual voltage drops equals the total applied voltage (VD1 + VD2 + VD3 = 24 V).V = 4005 × √Pv (Pv in in. w.c.); e.g., 4005 × √0.25 = 2003 ft/min. Swinging-vane anemometer correction: velocity = instrument reading × √((460 + T) ÷ (460 + 68)).ACH = (cfm × 60) ÷ room volume in ft³; ACH50 = (cfm50 × 60) ÷ conditioned volume; e.g., (1,500 × 60) ÷ 12,000 = 7.5.NS = (120 × frequency) ÷ number of poles; 4-pole at 60 Hz = (120 × 60) ÷ 4 = 1800 RPM, and with 4%–5% slip actual full-load speed ≈ 1750 RPM.COP = refrigeration effect ÷ heat of compression = (compressor inlet h − evaporator inlet h) ÷ (compressor outlet h − compressor inlet h); (179 − 116) ÷ (198 − 179) = 63 ÷ 19 = 3.32:1.Q = U × area × temperature difference, applied as HTM = U × HTD then load = area × HTM; e.g., wall HTM = 0.07 × 50 = 3.50, 136 ft² × 3.50 = 476 Btuh; glass HTM = 0.30 × 50 = 15.00, 60 ft² × 15.00 = 900 Btuh; net wall = (24 ft × 9 ft) − 60 ft² glass − 20 ft² door = 136 ft². Single glass constant method: 1.13 × 70°F TD × 12 ft² = 949 Btu/hr.Slab heat loss = building perimeter (linear feet) × 18 Btu/hr per foot (0°F outdoor design temp), added to above-ground losses; infiltration heating load counts sensible only: Qs = 0.018 × CFH × TD.Friction rate = (ASP ÷ TEL) × 100 = (0.20 ÷ 250) × 100 = 0.08 in. WC per 100 ft; keep aspect ratio near 1:1 (20×5 duct has 50 in. perimeter vs 40 in. for 10×10 at equal 100 in² area = 25% more material); straight duct length = sum of labeled segments (28 + 22 + 15 = 65 ft, excluding elbow allowances); outdoor-air % = outdoor cfm ÷ total mixed cfm (1,000 ÷ 4,000 = 25%).