Exam Cheat Sheet · Quick Reference
Oklahoma HVACR Journeyman Unlimited
Oklahoma · PSI Services Contractor
Oklahoma State Portion 70 questions
Key Distinctions
A pictorial diagram shows all connections plus the approximate physical location of devices in the unit (and often wire colors), while a ladder diagram shows the order of component operation as horizontal rungs (individual circuits with controls and loads) between two vertical power-supply lines, with devices near the top energized first.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 18 - Electrical Troubleshooting Fundamentals, Page 369 (Section 18.2.2) (20th ed.: Chapter 16, Section 16.1.1)Both use electromagnetic coils and can be rebuilt, but the motor starter's distinguishing feature is built-in overload protection that prevents motors from burning out or overheating.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 341 ("Contactors and Motor Starters") (20th ed.: Chapter 16, Section 16.3.5 — Contactors and Motor Starters)A weight-operated current relay must be mounted in a level position, whereas a current relay using a rotary solenoid can be mounted in any position.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 338 ("Current Relays") (20th ed.: Chapter 16, Section 16.3.5 — Current Relays)An SSR switches circuits with electronic components (transistors, SCRs, triacs) and has no physical movement of mechanical parts, and is typically used to start single-phase motors; electromagnetic relays switch mechanically.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 345 ("Solid-State Relays") (20th ed.: Chapter 16, Section 16.3.5 — Solid-State Relays)A hard lockout shuts the system down for an unspecified time after a failed trial for ignition and requires a service call or power interruption to reset, while a soft lockout automatically retries after a waiting period.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 33 - Gas-Fired Heating Systems, Page 770 (20th ed.: Page 1129)BRI is a specifically diagnosable illness caused by airborne agents whose symptoms do NOT disappear when the occupant leaves the building, while SBS has no specific cause or identifiable illness and its symptoms disappear when occupants leave.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 29 - Air Quality, Page 647 (20th ed.: Page 730)K-value is heat passing through one square foot of material one inch thick in one hour per 1°F difference (Btu·in/hr·ft²·°F), while C-value is based on the material's actual measured thickness rather than a standardized 1-inch thickness.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 32 - Heating and Cooling Loads, Page 717 (20th ed.: Page 986)The subcooling method is used to check charge on systems with thermostatic expansion valves (low subcooling suggests undercharge, high suggests overcharge), while the superheat method is used on fixed-orifice systems such as capillary tubes.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 12 - Working with Refrigerants, Page 221 (20th ed.: Page 236)Turning the range screw clockwise raises both cut-in and cut-out an equal amount (differential unchanged), while the differential adjustment turned clockwise raises only the cut-out pressure and does not affect cut-in.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 17 - Electrical Control Systems, Page 333 (Section 17.4.4) (20th ed.: Chapter 16, Section 16.3.4 — Low-Pressure Motor Controls)Three-phase supply is already phase-split so the motor develops starting torque without start windings or capacitors, and delivers constant power because there is never an instant when all voltages are zero; single-phase motors need start components.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 16 - Electric Motors, Page 308 (Section 16.2.2) (20th ed.: Chapter 15, Section 15.2.2)In an HSI system the glow coil only ignites and cannot sense flame; a separate flame rod performs flame rectification sensing, and if it is dirty or oxidized the module closes the gas valve seconds after ignition (HSI systems use no thermocouple).
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 33 - Gas-Fired Heating Systems, Page 765 (20th ed.: Pages 1126-1128 (Sections 41.5.4 and 41.6.1))Recovering at the liquid line takes refrigerant as subcooled liquid (after the condenser), which speeds recovery, while the discharge service valve delivers superheated high-pressure vapor, making recovery slower and less efficient.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 50 - Servicing Commercial Systems, Page 1233 (20th ed.: Page 1500)A radial system runs individual branch ducts directly from the central plenum to each outlet with no trunk line, while a perimeter loop system (used with downflow furnaces in slab homes without basements) has branches feeding a perimeter duct cast in the slab.
Modern Refrigeration and Air Conditioning (22nd ed.), Chapter 30 - Air Distribution, Page 672 (20th ed.: Page 755)Per IMC 603.2, Manual D is an accepted duct-sizing method for a single dwelling unit (along with manufacturer's instructions or other approved methods); Manual J is for load calculations and Manual S is for equipment selection, and the ASHRAE Handbook of Fundamentals is required for buildings other than single dwelling units.
IMC 2024 Section 603.2Key Terms
Formulas to Know
R = E ÷ I and I = E ÷ R; e.g., 240 V ÷ 10 A = 24 Ω; 24 V ÷ 8 Ω = 3 A (in a series circuit the same current flows through every load); 120 V ÷ 24 Ω = 5 A; 120 V ÷ 25 A = 4.8 Ω.P = I × E; e.g., 20 A × 120 V = 2400 W; 15 A × 240 V = 3600 W; 8 A × 240 V = 1920 W; 4 A × 120 V = 480 W; 1 A × 1 V = 1 W.Differential = difference between cut-out and cut-in (always subtract the lower value from the higher): heating = cut-out − cut-in, e.g., 74°F − 68°F = 6°F; cooling = cut-in − cut-out, e.g., 25°F − 15°F = 10°F.Subcooling = condensing (boiling) temperature at operating pressure − actual measured liquid temperature; e.g., 212°F − 190°F = 22°F.V = 4005 × √Pv (Pv in inches of water); e.g., 4005 × √0.25 = 4005 × 0.5 ≈ 2003 ft/min.Actual velocity = instrument reading × √[(460 + T) ÷ (460 + 68)], where T is actual duct temperature in °F.ACH = (airflow in cfm × 60 min) ÷ room volume in ft³; blower door: ACH50 = (cfm50 × 60) ÷ conditioned volume, e.g., (1,500 × 60) ÷ 12,000 = 7.5.1 kW = 3,413 Btu/hr; kW required = Btu/hr ÷ 3,413, e.g., 50,000 ÷ 3,413 = 14.65 kW.COP = refrigeration effect ÷ heat of compression = (compressor-in enthalpy − evaporator-in enthalpy) ÷ (compressor-out − compressor-in); e.g., (179 − 116) ÷ (198 − 179) = 63 ÷ 19 = 3.32:1.TEL = longest supply run effective length + longest return run effective length (e.g., 180 ft + 120 ft = 300 ft); Friction rate = (ASP ÷ TEL) × 100, e.g., (0.20 in. WC ÷ 250 ft) × 100 = 0.08 in. WC per 100 ft; equivalent length of a run = straight measured length + elbow allowances (65 ft + 2 × 25 ft = 115 ft); keep velocity at or below 700 fpm to avoid excessive noise.